(博奕論)北海道大學入學試題,1至100選最大數字

首先唔應該揀40或以下, 因為就算加左60都高唔過直接揀100
假設加到60分, 41=>101,...,100=>160
如果參加者眾, 直接揀100會比較好, 因為好大機會個個數都有人揀, 但另一方面揀4x可能可以出奇制勝, 但輸左就得4x分
如果人少少, 應該揀貼近100既數, 搏冇人同你一樣

99
搏成班人以為個個唔敢寫最大100, 所以就自己寫100
點知個個都咁諗就撞哂100

首先唔應該揀40或以下, 因為就算加左60都高唔過直接揀100
假設加到60分, 41=>101,...,100=>160
如果參加者眾, 直接揀100會比較好, 因為好大機會個個數都有人揀, 但另一方面揀4x可能可以出奇制勝, 但輸左就得4x分
如果人少少, 應該揀貼近100既數, 搏冇人同你一樣

99.99999999999999999999999999999999999

無話唔比小數

鬥多小數點後位

係個9度點一點咪得
循環數字

重點係簡一個你鍾意既數字
不能重覆係指你鍾意既原因
呢題跟本唔係數學題

一定100啦==
就算得你1個寫99 其他全部100 你都寫唔到個最大數字 都係冇分加 所以老閪都寫100

太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

99
搏成班人以為個個唔敢寫最大100, 所以就自己寫100
點知個個都咁諗就撞哂100

98
因為如果個個咁諗就撞哂99

太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

首先你要睇下試場有幾多考生
過一千人既話
老練都填100

所以你咪fail左

太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案

太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案