(博奕論)北海道大學入學試題,1至100選最大數字

941 回覆
111 Like 8 Dislike
2017-06-22 23:17:10
首先唔應該揀40或以下, 因為就算加左60都高唔過直接揀100
假設加到60分, 41=>101,...,100=>160
如果參加者眾, 直接揀100會比較好, 因為好大機會個個數都有人揀, 但另一方面揀4x可能可以出奇制勝, 但輸左就得4x分
如果人少少, 應該揀貼近100既數, 搏冇人同你一樣
2017-06-22 23:18:40
可能係講緊隻數字size

9
2017-06-22 23:24:09
唔係22定23咩
2017-06-22 23:27:29
99
搏成班人以為個個唔敢寫最大100, 所以就自己寫100
點知個個都咁諗就撞哂100
2017-06-22 23:33:11
首先唔應該揀40或以下, 因為就算加左60都高唔過直接揀100
假設加到60分, 41=>101,...,100=>160
如果參加者眾, 直接揀100會比較好, 因為好大機會個個數都有人揀, 但另一方面揀4x可能可以出奇制勝, 但輸左就得4x分
如果人少少, 應該揀貼近100既數, 搏冇人同你一樣

2017-06-22 23:35:37
99
搏成班人以為個個唔敢寫最大100, 所以就自己寫100
點知個個都咁諗就撞哂100

98
因為如果個個咁諗就撞哂99
2017-06-22 23:38:08
70以上唔洗諗
1-31都唔洗諗
一定有人用生日日期
40-60中間都會有人揀

要睇人數多定少
多人就33-39估一個
少人可以試61-69
2017-06-22 23:39:18
首先唔應該揀40或以下, 因為就算加左60都高唔過直接揀100
假設加到60分, 41=>101,...,100=>160
如果參加者眾, 直接揀100會比較好, 因為好大機會個個數都有人揀, 但另一方面揀4x可能可以出奇制勝, 但輸左就得4x分
如果人少少, 應該揀貼近100既數, 搏冇人同你一樣


睇錯題目
2017-06-22 23:41:06
econ好似有教過呢個concept
2017-06-22 23:41:44
99.99999999999999999999999999999999999

無話唔比小數

鬥多小數點後位

係個9度點一點咪得
循環數字

冇得輸
2017-06-22 23:43:36
重點係簡一個你鍾意既數字
不能重覆係指你鍾意既原因
呢題跟本唔係數學題
2017-06-22 23:46:03
重點係簡一個你鍾意既數字
不能重覆係指你鍾意既原因
呢題跟本唔係數學題

只係你唔明數學
2017-06-22 23:48:02
一定100啦==
就算得你1個寫99 其他全部100 你都寫唔到個最大數字 都係冇分加 所以老閪都寫100

有無睇清楚題目架
2017-06-22 23:48:30
太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works
2017-06-22 23:49:10
99
搏成班人以為個個唔敢寫最大100, 所以就自己寫100
點知個個都咁諗就撞哂100

98
因為如果個個咁諗就撞哂99

97
因為如果個個咁諗就撞哂98
2017-06-22 23:50:16
有幾多人先?
2017-06-22 23:50:29
太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案
2017-06-22 23:52:39
1
ko
2017-06-22 23:53:44
69
成日同男朋友玩
2017-06-22 23:54:53
首先你要睇下試場有幾多考生
過一千人既話
老練都填100

所以你咪fail左


題目有講點先算fail?
照佢個玩法
最多都係得一個人高過100分
仲有機會冇人高過100分添
2017-06-22 23:57:34
太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案


study下Nash Equilibrium先啦
2017-06-22 23:59:47
太長唔想用中文打

The strategy of choosing 100 is a weakly dominant strategy.

Consider a player, Alice. We only need to consider two cases:

Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.

Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.

The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.

實際上唔係

it sounds good but it never works

好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案


有問題
前設係唔係如果成堆人寫100
個堆100就輸哂 (取消資格)
咁寫99 個個人會贏
如果冇呢個前設就寫硬100
如果有
case 2 Alice 寫99未必輸
吹水台自選台熱 門最 新手機台時事台政事台World體育台娛樂台動漫台Apps台遊戲台影視台講故台健康台感情台家庭台潮流台美容台上班台財經台房屋台飲食台旅遊台學術台校園台汽車台音樂台創意台硬件台電器台攝影台玩具台寵物台軟件台活動台電訊台直播台站務台黑 洞