上面吹到nash equilibrium on the condition that all players are rational
但總有一班人比理性更理性,會諗多幾步,咁100咪會出事囉
真係入學試嘅話揀得100嘅可以將份卷歸零都得
唔係好明你意思
寫100 再大聲講因為100係冇得輸個d 可以直接dq唔收
一打唔洗找
上面吹到nash equilibrium on the condition that all players are rational
但總有一班人比理性更理性,會諗多幾步,咁100咪會出事囉
真係入學試嘅話揀得100嘅可以將份卷歸零都得
唔係好明你意思
寫100 再大聲講因為100係冇得輸個d 可以直接dq唔收
個post好多文盲
搵一個人做媒
假設全場玩家都知發生咩事同清楚規則
一開始同上面講嘅一樣
沖出去話自己填左100
然後個frd再沖出黎做媒 話撞鳩自己個100
等大家由99開始再諗
但其實個frd冇填100
最後就確保得一個100
搵一個人做媒
假設全場玩家都知發生咩事同清楚規則
一開始同上面講嘅一樣
沖出去話自己填左100
然後個frd再沖出黎做媒 話撞鳩自己個100
等大家由99開始再諗
但其實個frd冇填100
最後就確保得一個100
真心分析唔係鳩講架
重點係簡一個你鍾意既數字
不能重覆係指你鍾意既原因
呢題跟本唔係數學題
只係你唔明數學
搵一個人做媒
假設全場玩家都知發生咩事同清楚規則
一開始同上面講嘅一樣
沖出去話自己填左100
然後個frd再沖出黎做媒 話撞鳩自己個100
等大家由99開始再諗
但其實個frd冇填100
最後就確保得一個100
真心分析唔係鳩講架
前提係其他99個都信你係填100
太長唔想用中文打
The strategy of choosing 100 is a weakly dominant strategy.
Consider a player, Alice. We only need to consider two cases:
Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.
Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.
The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.
點解咁多弱智
上面吹到nash equilibrium on the condition that all players are rational
但總有一班人比理性更理性,會諗多幾步,咁100咪會出事囉
真係入學試嘅話揀得100嘅可以將份卷歸零都得
唔係好明你意思
寫100 再大聲講因為100係冇得輸個d 可以直接dq唔收
9唔搭8 咩無啦啦咩大聲講
我意思game theory既話, 100岩
但現實100唔會岩
太長唔想用中文打
The strategy of choosing 100 is a weakly dominant strategy.
Consider a player, Alice. We only need to consider two cases:
Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.
Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.
The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.
未追哂post
首先傻仔一定揀100
賭仔心態會揀90-99
揀得過嘅得1-89
呢啲情況,㨂質數比較有利
而最大質數係89,但有89有9,依然有大嘅感覺,而且貼近90 range,相信依然係半熱門
數落去下一個係83,我會揀83
這麼認真地9Up 辛苦你了
太長唔想用中文打
The strategy of choosing 100 is a weakly dominant strategy.
Consider a player, Alice. We only need to consider two cases:
Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.
Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.
The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.
太長唔想用中文打
The strategy of choosing 100 is a weakly dominant strategy.
Consider a player, Alice. We only need to consider two cases:
Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.
Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.
The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.
實際上唔係
it sounds good but it never works
好明顯考你既唔係實際你填既數字而係背後既concept
呢個咪就係正確答案
贏既條件應該係揀到
冇同其他人重複既數入面, 最大既數
既如果其他人全揀100, 我就算揀1都贏到
所以case 2唔成立
就咁睇應該揀
n such that P(all unique numbers<n)*P(n is unique) is max
問題係唔知P(n is unique)係幾多
太長唔想用中文打
The strategy of choosing 100 is a weakly dominant strategy.
Consider a player, Alice. We only need to consider two cases:
Case 1: The largest number chosen by the rest of the group is strictly less than 100. Then, Alice can always win by choosing 100, but if she may lose if she chooses a number less than 100.
Case 2: The largest number chosen by the rest of the group is 100. Then, Alice will lose no matter which number she chooses, so she is indifferent between all possible strategies.
The conclusion means that all (rational) players should choose 100, leading to a Nash equilibrium outcome in which all players gain zero point.
題目都未識睇