我反對
0.9999999...x10 咁少左一個小數位囉 點減到齊頭
你咁即係話0.999 x10 =9.999 邊忽合理
...係無限個小數位
無限同無限減一個冇分別？
首先你要搞清楚咩叫無限
所以我講黎係想提你 你o既講法係有assumption
有討論空間 唔好以為一定係真理
無限唔係一個數值
你肯定你對無限的定義絕對正確？
淨係嘈無限的定義已經可以嘈幾個世紀
我甚至可以質疑人作為有限的生物係唔會理解到咩叫無限
巴打涉獵少少哲學會明我講咩
你睇完幾次數學危機，明白左呢堆真理先講啦
讀數D人真係好固執
No doubt 嘅野d人都可以討論咁耐
0.999999999999=/=1
但係0.999999999999.........=1
話1-0.99999...=0.000....1個啲不如去讀多次小學
lim 1 - x = 1
x→0
上面個 = 1 係指無限接近 1 而唔係等於 1 OK？
利申：未學過微分。
錯concept
當x好接近0而唔等於0時，1-x係好接近1而且唔等於1，但係個limit係等於1而唔係無限接近1
Z_p呢
應該係...?[quote]0.999999999999=/=1
但係0.999999999999.........=1
話1-0.99999...=0.000....1個啲不如去讀多次小學
[quote]0.999999999999=/=1
但係0.999999999999.........=1
話1-0.99999...=0.000....1個啲不如去讀多次小學
佢所謂既0.000....1其實係0.1,0.01,0.001...既limit[/quote]
啲人係以為無限個0之後有個1係度
同埋呢個係咩limit黎
Z_p呢
已經還返晒比Professor
廢事有盲撚唔識google
If the common ratio r lies between −1 and 1 , we can have the sum of an infinite geometric series.
The sum S of an infinite geometric series with −1<r<1 is given by the formula,
S=a/(1−r), where a=first term, r=common ratio
when a=9/10, r=1/10
0.999999……
=9/10+9/100+9/1000+……+9/10^n (where n=infinity)
=(9/10)/(1-1/10)
=1
https://www.varsitytutors.com/hotmath/hotmath_help/topics/infinite-geometric-series
唔撚識英文呀
Z_p呢
已經還返晒比Professor
無記錯p-adic入面就唔岩，但係euclidean norm就會岩呢樣野
心諗你地係到講一大論做乜野
廢事有盲撚唔識google
If the common ratio r lies between −1 and 1 , we can have the sum of an infinite geometric series.
The sum S of an infinite geometric series with −1<r<1 is given by the formula,
S=a/(1−r), where a=first term, r=common ratio
when a=9/10, r=1/10
0.999999……
=9/10+9/100+9/1000+……+9/10^n (where n=infinity)
=(9/10)/(1-1/10)
=1
https://www.varsitytutors.com/hotmath/hotmath_help/topics/infinite-geometric-series
唔撚識英文呀
咁就去食屎啦
廢事有盲撚唔識google
If the common ratio r lies between −1 and 1 , we can have the sum of an infinite geometric series.
The sum S of an infinite geometric series with −1<r<1 is given by the formula,
S=a/(1−r), where a=first term, r=common ratio
when a=9/10, r=1/10
0.999999……
=9/10+9/100+9/1000+……+9/10^n (where n=infinity)
=(9/10)/(1-1/10)
=1
https://www.varsitytutors.com/hotmath/hotmath_help/topics/infinite-geometric-series
唔撚識英文呀
咁就去食屎啦
仲爭執緊
其實唔係讀數嘅人真係唔洗咁執著，想要了解哂成件事就不如自己好好wiki下，睇唔明先上黎，仲會學得更多
廢事有盲撚唔識google
If the common ratio r lies between −1 and 1 , we can have the sum of an infinite geometric series.
The sum S of an infinite geometric series with −1<r<1 is given by the formula,
S=a/(1−r), where a=first term, r=common ratio
when a=9/10, r=1/10
0.999999……
=9/10+9/100+9/1000+……+9/10^n (where n=infinity)
=(9/10)/(1-1/10)
=1
https://www.varsitytutors.com/hotmath/hotmath_help/topics/infinite-geometric-series
唔撚識英文呀
咁就去食屎啦
仲爭執緊
其實唔係讀數嘅人真係唔洗咁執著，想要了解哂成件事就不如自己好好wiki下，睇唔明先上黎，仲會學得更多
我都唔明數呢家野已經好好討論，岩就岩錯就錯....
做咩要咁勞氣
我諗唔係讀數嘅人如果只係想靠人地回帖就搞清楚，都唔係一件易事Z_p呢
廢事有盲撚唔識google
If the common ratio r lies between −1 and 1 , we can have the sum of an infinite geometric series.
The sum S of an infinite geometric series with −1<r<1 is given by the formula,
S=a/(1−r), where a=first term, r=common ratio
when a=9/10, r=1/10
0.999999……
=9/10+9/100+9/1000+……+9/10^n (where n=infinity)
=(9/10)/(1-1/10)
=1
https://www.varsitytutors.com/hotmath/hotmath_help/topics/infinite-geometric-series
唔撚識英文呀
咁就去食屎啦
仲爭執緊
其實唔係讀數嘅人真係唔洗咁執著，想要了解哂成件事就不如自己好好wiki下，睇唔明先上黎，仲會學得更多
我都唔明數呢家野已經好好討論，岩就岩錯就錯....
做咩要咁勞氣
咁係幾難明嘅，你諗下解釋 0-1入面嘅 real number 數目 同0-100入面有嘅 real number 數目一樣多俾普通人聽，佢聽完就算明，內心都會抗拒一陣。
而0.9999....呢個問題，比較嚴謹嘅論證我係喺 real analysis 入面學嘅
假設0.99999999999999.......=1 正確
設x=0.9999999......=1
x-x=0 , 1-0.999......=0.00...01
0=0.0000...01
設k為一常數
做0.000...01*k=1
0*k=0.00.01*k
0=1
0=1+1=2
0=0+0+0=3
1=2=3=............
一蚊都無 都可以好滿足就係咁解
假設0.99999999999999.......=1 正確
設x=0.9999999......=1
x-x=0 , 1-0.999......=0.00...01
0=0.0000...01
設k為一常數
做0.000...01*k=1
0*k=0.00.01*k
0=1
0=1+1=2
0=0+0+0=3
1=2=3=............
一蚊都無 都可以好滿足就係咁解
