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10+10-10點計

你係咪hku maths?

我會考有C

Prove or disprove square root of 43 is transcendental

10+10-10點計

太難
有無簡單D

唔識做

Prove or disprove square root of 43 is transcendental

square root of 43 is defined to be the solution of x^2=43
hence it is the root f(x)=x^2-43, where f(x) in Z[x]
Thus, it is algebraic

推

[img]https://na.cx/i/xXvRj23.jpg[img]



唔識做

1
2;3
4;5;6
7;8;9;10

T(n)=n-th term of (1,3,6,10...)
a_n = 2^T(n)
b_1=2a_n = 2^(T(n)+1)
b_(n+1) = 2^T(n+1)

[img]https://na.cx/i/xXvRj23.jpg[img]



唔識做

1
2;3
4;5;6
7;8;9;10

T(n)=n-th term of (1,3,6,10...)
a_n = 2^T(n)
b_1=2a_n = 2^(T(n)+1)
b_(n+1) = 2^T(n+1)

For n >1,
a_1=2^(T(n-1)+1)
a_1+a_2+...+a_n=GS sum=...
=(2^n-1)a_1
For n=1, this is also true.

[img]https://na.cx/i/xXvRj23.jpg[img]



唔識做

1
2;3
4;5;6
7;8;9;10

T(n)=n-th term of (1,3,6,10...)
a_n = 2^T(n)
b_1=2a_n = 2^(T(n)+1)
b_(n+1) = 2^T(n+1)

For n >1,
a_1=2^(T(n-1)+1)
a_1+a_2+...+a_n=GS sum=...
=(2^n-1)a_1
For n=1, this is also true.

b_1b_2...b_n
=2^[(T(n)+1)+(T(n)+2)+(T(n)+3)+...+(T(n)+(n+1))]
=2^[(n+1)T(n)+T(n+1)]
=...

仲有無

[img]https://img.eservice-hk.net/upload/2017/03/16/163021_6d3ad85e9ccdf31e5eeea2b98f852929.jpg[img]
補習狗

做乜鳩

無人問啦

[img]https://img.eservice-hk.net/upload/2017/03/16/163021_6d3ad85e9ccdf31e5eeea2b98f852929.jpg[img]
補習狗

做乜鳩

補習都唔比

解釋下咩係injective surjective

樓豬識m2既數?

1-1=？

如果n>1係整數，係咪會搵到正整數a,b,c令到4/n=1/a + 1/b +1/c?

好Q難 諗諗先

皮膚+樣=身材

腳=？