有錯請指正Another intuitive question:Answer
Let f(x) = a^x where a >2
Then we have f(i) = a^i.
Is it correct?
i = i^(4n+1)
a^i = a^i^(4n+1) = a^(4n+1)^i
for any real integer n>0
Then a^i is multi-valued, which defies the definition of function
So f(i) is not defined.