python Csv問題

256 回覆
0 Like 55 Dislike
2020-11-04 14:54:19
我係怕有啲野理解錯
不過英文都ok
2020-11-05 13:16:51
2020-11-05 14:40:29
可以挑戰下
呢個未試過
2020-11-05 15:06:03
真心怕被人block ip
2020-11-05 16:36:08
如果我想df[6]出現"Bigger","Smaller"時
就會print "error"
如果冇出現就print "Done"

我咁樣好似唔得

status = np.where((df[6] == 'Bigger') | (df[6] == 'Smaller'),'Error','Done')
print(status) 
2020-11-05 16:53:55
應該係問 .isin 應該點用?
2020-11-06 14:32:19
係唔係用joblib parallel ?
2020-11-09 15:07:03
我發現可以係個html個到加號碼就可以搵到我想要既個頁
而我想根據csv既col3去加到html咁crawler
唔洗.send_keys(Keys.RETURN)咁crawler
但我又卡左係到

2020-11-17 20:52:10
請教吓,你點係留言做到code syntax color highlight?連登秘技?
2020-11-17 20:53:07
唔好搞咁多野
讀data一定係pandas
2020-11-17 23:28:42
""" Insert code block """

print("Hello World!")
2020-11-18 00:56:37
成功咗!
import lihkg as ld

''' testing lihkg api '''

class Lihkger:
    def __init__(self, name, pswd):
        ld.login(name, pswd)

    def reply(self, msg):
        ld.reply(msg)

me = Lihkger(myname, mypswd)

me.reply('hello world with color')

真係連登秘技喎
btw如果有錯syntax立即變返灰色
2020-11-18 07:31:50
Google Colab?
2020-11-18 13:38:49
Atom portable?
2020-11-27 09:39:36
我想問 df2 A value就一定unique
咁df1既A value 係唔係可以重複?

同如果想張df1既col B根據col A 咁入df2 既col B value
係唔係咁?
df1["B"] = df1[“A”].map(df2.set_index(“A”)[“B”])
2020-11-27 13:45:24
我想問如果
df1[A] 既val 冇係df2[A]出現
咁個df1[B]既val就出"Erorr"
咁要點改?

而加用緊
df1[“A”].map(df2.set_index(“A”)[“B”])
2020-11-28 00:33:10
咩叫出Erorr
what is traceback
2020-11-28 01:47:10
因為df2[A]係unique
而df1[A]會重複
如果 df1[A]個行冇同df2[A]任何一行一樣
df1[B]個格就會入str(’Error’)
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