計劃進修PhD/Research討論區 (11) All money is a matter of belief

1001 回覆
5 Like 2 Dislike
2017-04-17 00:46:11
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

可以
2017-04-17 00:47:13
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了
2017-04-17 00:50:18
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了


其實要製造呢D function好簡單: 求其拎個differentaible function, 如果佢個derivative is not continuous的話, 個derivative就會係counter example
2017-04-17 00:50:48
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?
2017-04-17 00:52:06
個po推得咁快
2017-04-17 00:53:49
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了


其實要製造呢D function好簡單: 求其拎個differentaible function, 如果佢個derivative is not continuous的話, 個derivative就會係counter example


你讀Analysis果陣就會知點解
2017-04-17 00:54:06
個po推得咁快

因為有數學
2017-04-17 00:56:42
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

2017-04-17 00:56:54
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了


其實要製造呢D function好簡單: 求其拎個differentaible function, 如果佢個derivative is not continuous的話, 個derivative就會係counter example


你讀Analysis果陣就會知點解

2017-04-17 00:57:45
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra

2017-04-17 00:59:01
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra


2017-04-17 00:59:43
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra


2017-04-17 01:00:09
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra



2017-04-17 01:01:26
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra



2017-04-17 01:01:40

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了


其實要製造呢D function好簡單: 求其拎個differentaible function, 如果佢個derivative is not continuous的話, 個derivative就會係counter example



有性趣知點解
2017-04-17 01:03:53
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra




2017-04-17 04:07:30
Consider f=0 if rational, =1 if irrational

我都係咁諗,不過搵唔到value in(0,1)咪做唔到個conclusion

但係條theorem holds for constant function wo

constant function本身continuous架啦

I mean, 所以攞個value 係inclusive
即係 [f(a), f(b)] assuming f(a)<f(b)


sin(1/x)得唔得

下年anal要靠你carry了

唔知撞唔撞時間 諗緊要anal定bra

bra係咩?

algebra





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