[數撚圍爐區] 祝手巴日日無工開, 想出紙永遠失敗 (54)

1001 回覆
1 Like 3 Dislike
2021-11-16 14:49:43

都係唔知咩嚟
2021-11-16 14:50:49
或者簡單D
given
u_x + u_y = 0
你會點solve?
2021-11-16 14:51:24
Wolfram alpha
2021-11-16 14:53:03
唔比用計數機/電腦
2021-11-16 15:18:22
sub 咗
x=唔識打嘅符號
y=(唔識打嘅符號-唔識打嘅符號2)
2021-11-16 15:18:52
然後就唔知點做了
2021-11-16 15:21:08

tutor sd咗呢張相俾我
2021-11-16 15:33:01
2021-11-16 18:18:08
原來佢出錯題目

咁樣先啱
2021-11-16 22:50:11
你係咪唔知咩叫characteristics
2021-11-17 00:22:34
what is characteristics
2021-11-17 00:38:34
例如 u_x + u_y = 0 條chatacteristics咪 a(t) = (x0 + t, y0 + t)
解1d wave equation會用到
2021-11-17 03:02:37
2021-11-17 03:18:47
2021-11-17 03:45:06
2021-11-17 04:13:39
2021-11-17 06:00:02
The PDE in question can be reduced to an ODE along characteristic lines. If the ODE is nice, you get an invariant quantity along the characteristic lines.
2021-11-17 06:03:50
u_x+u_y=0 where subscript denotes partial derivative, 無端端走t出黎??
2021-11-17 06:09:52
444你都識講
將pde變成ode in t lor
2021-11-17 06:10:42
2021-11-17 06:12:26
2021-11-17 06:15:32
Constant a 對我容易D.

u_t+a*u_x=0 where subscript denotes partial derivative.

Let dx/dt=a, then
u_t+dx/dt*u_x=0

And from the definition of total derivative, the equation is now:
u_t+dx/dt*u_x=Du/Dt=0 along dx/dt=a.

No it becomes an ODE:
Du/Dt=0 along dx/dt=a
u=Constant along dx/dt=a
Given an initial condition u0(x), u(t,x)=u0(x-at).
係用characteristic line 將個solution trace返去initial condition.
2021-11-17 06:17:01
t係吾係independent variable?
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