5.4.4a部份係已經唔識做
用image of function on a compact set都係compact再用extreme value theorem去證明有M?M冇理由geometric series of (1/2)^n咁易啩?
高山一実2018-11-17 16:53:18
睇幅圖第一個maximum好似喺二進制x=0.10101010...嗰度
Billybug大哥2018-11-17 17:18:48
Let m,n be two distinct numbers,
0 = 0
m x 0 = n x 0
m = n
which leads to contradiction.
By contradiction, m and n are the same.
Therefore, all numbers in this world are indeed the same.
幸福安泰吻2018-11-17 18:07:52
你哋prefer 學咗basis 先定linear transformation 先
吾不會數學2018-11-17 18:09:59
視乎你想係邊個位講representation
吾不會數學2018-11-17 18:10:21
但係無basis點講rank nullity?
夢追人2018-11-17 20:37:30
basis
高山一実2018-11-17 20:54:45
linear transform R^n to R^m
-> basis
-> linear transform V to W