如果我想計數
假設我有4個observations : 1, 2,3,4
咁第3個就會係(1*0.8+2)*0.8+3 = 5.24
想順序顯示第1個observation 第2個咁
d code 應該係點🙏🏻🙏🏻🙏🏻
Python 新手問題
Easonnnn
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唔係好明 講清楚d ok?
Output:
1
2.8 <———-(1*0.8)+2
5.24 <———((1*0.8)+2)*0.8+3
8.192
1
2.8 <———-(1*0.8)+2
5.24 <———((1*0.8)+2)*0.8+3
8.192
你係算式唔識做定係做唔到順序出result?
算式唔識做🙏🏻
def cal(n):
sum = 1
print(sum)
for i in range(2, n+1):
sum = (sum * .8) + i
print(sum)
cal(4)是但諗 唔知係唔係咁
利申: 都係學左無耐
x = pd.Series([1,2,3,4])
n = len(x)
y = [(x[:j] * [0.8**(j-i-1) for i in range(j)]).sum() for j in range(1, n+1)]
n = len(x)
y = [(x[:j] * [0.8**(j-i-1) for i in range(j)]).sum() for j in range(1, n+1)]
import itertools
print (list(itertools.accumulate([1, 2, 3, 4, 5], lambda x,y : x*0.8+y)))
obs = [1,2,3,4,7,8,9,10]
for i in range(1, len(obs)):
obs[i] += obs[i-1]*0.8
print(obs)
for i in range(1, len(obs)):
obs[i] += obs[i-1]*0.8
print(obs)