唔識個loop 應該點寫
有冇高人指點一下
javascript 一問
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初學
唔識個loop 應該點寫
有冇高人指點一下
唔識個loop 應該點寫
有冇高人指點一下
forloop // do sth on x
{
forloop // do sth on y
{
forloop // do sth on z
{
}
}
}
{
forloop // do sth on y
{
forloop // do sth on z
{
}
}
}
forloop // do sth on x
{
forloop // do sth on y
{
forloop // do sth on z
{
if (x - 2y + 3z == 0)
then print result
}
}
}
for (let x = 1; x <= 5; x++)
for (let y = 6; y <= 10; y++)
for (let z = 3; z <= 7; z++)
for (let y = 6; y <= 10; y++)
for (let z = 3; z <= 7; z++)
我仲差啲咩 真係唔係好識啲詳細既code...
js 有if then 架咩
我唔識今晚要交
今晚要交重新學過啦咁你
google下for loop點用
google下for loop點用
都唔止係for loop 問題
中學功課黎？
啱啱寫完，但唔想害左你。其實樓上已經俾左一半答案。下一半係呢度
講明先，其實我唔識javascript.
if ( (x-(2*y)+(3*z)) == 0){
console.log("x = " + x + ", y = " + y + ", z =" + z);
}
for loop syntax, https://www.w3schools.com/js/js_loop_for.asp
你可以用以下呢個寫。
https://codepen.io/pen/
講明先，其實我唔識javascript.
if ( (x-(2*y)+(3*z)) == 0){
console.log("x = " + x + ", y = " + y + ", z =" + z);
}
for loop syntax, https://www.w3schools.com/js/js_loop_for.asp
你可以用以下呢個寫。
https://codepen.io/pen/
你已經害左佢
你啱。[1, 2, 3, 4, 5].forEach(x => {
[6, 7, 8, 9, 10].forEach(y => {
[3, 4, 5, 6, 7].forEach(z => {
if (x - 2 * y + 3 * z == 0) {
console.log("x = " + x + ", y = " + y + ", z =" + z);
};
})
})
});
[6, 7, 8, 9, 10].forEach(y => {
[3, 4, 5, 6, 7].forEach(z => {
if (x - 2 * y + 3 * z == 0) {
console.log("x = " + x + ", y = " + y + ", z =" + z);
};
})
})
});
重讀啦
錯撚哂
錯撚哂
for x in range(1,6):
for y in range(6,11):
for z in range(3,8):
if ( x - 2 * y + 3 * z == 0 ):
print("x={}, y={}, z={}".format(x,y,z))
呢條問題可以變得好有趣，如果想optimize個time complexity嘅話 
，例如呢個case係有辦法唔洗寫三個loop，因為你係搵緊一個matrix嘅null space，loop完頭兩個variable，最後嗰個variable如果係within range嘅話，佢個value必然係unique，所以唔洗loop佢
，例如呢個case係有辦法唔洗寫三個loop，因為你係搵緊一個matrix嘅null space，loop完頭兩個variable，最後嗰個variable如果係within range嘅話，佢個value必然係unique，所以唔洗loop佢唔好水鳩人啦
咁簡單都話有趣
咁簡單都話有趣
唔係呀，而家講緊O(n^3)同O(n^2)嘅分別喎
樓主企都未企到你就教人跑
var x = [1, 2, 3, 4, 5];
var y = [6, 7, 8, 9, 10];
x.forEach(xNum => {
y.forEach(yNum => {
result = xNum + 2 * yNum;
remainer = (xNum + 2 * yNum) % 3;
if (!remainer) {
console.log("x: " + xNum + " y: " + yNum + " z: " + result / 3);
}
})
})